BRIDGE
RECTIFIER:
 In replacement of
full wave rectifier we use Full wave bridge rectifier for rectification, change AC to DC
current. But the question is here why we replace full wave rectifier, because
bridge rectifier is more reliable than full wave it provide quantity of DC
current as output. Overall the phenomenon of working of bridge is likely as
full wave.
CONSTRUCTION:
![]()  | 
| Bridge rectifier | 
DERIVATION:
          (1)   
 Vavg =Area/time =  2Vp /ㄫ
          (2)   
 Vpout = Vpsec – 1.4 where
            Vpsec = Number of turn * primary volt = ղ *Vpri
               If the primary
voltage is given in rms then to find Vpri, multiply the rms value to 
              under root 2. same process goes for Vpsec
               Such
as   Vpri = √2 *Vrms  
           (3)   
PIV= Vpout + 0.7
NUMERIC =1
  Determine the peak
output voltage for the bridge rectifier. Assuming the practical model. What PIV
rating is required for the diodes? The transformer is specified to have a 12rms
secondary voltage for the standard 120V across the primary.
Data:
                Vrms = 12V
                Vpout =?
Solution:
                Vpout = Vpsec – 1.4 where 
                Vpsec =√2*12V 
                           = 16.97V
So 
                 Vpout =16.97 -1.4
                            = 15.57V
And PIV required is 
                  PIV = Vpout+ 0.7
                         = 15.57 + 0.7
                         = 16.2V
PEAK VOLTAGE:
                  P=V/I 
            and I =P/V







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